-x^2=3x-54

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Solution for -x^2=3x-54 equation:



-x^2=3x-54
We move all terms to the left:
-x^2-(3x-54)=0
We add all the numbers together, and all the variables
-1x^2-(3x-54)=0
We get rid of parentheses
-1x^2-3x+54=0
a = -1; b = -3; c = +54;
Δ = b2-4ac
Δ = -32-4·(-1)·54
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-15}{2*-1}=\frac{-12}{-2} =+6 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+15}{2*-1}=\frac{18}{-2} =-9 $

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